Find the Perfect Square Trinomial z^2-14z

$z^{2} - 14 z$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $z$ by $2$ and square the result.

Divide $14$ by $2$ .

${(- 1 \cdot 7)}^{2}$

Multiply $- 1$ by $7$ .

${(- 7)}^{2}$

Raise $- 7$ to the power of $2$ .

$49$

Step 2

Add $49$ to get the perfect square trinomial.

$z^{2} - 14 z + 49$