Find the Perfect Square Trinomial z^2-16z+

$z^{2} - 16 z +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $z$ by $2$ and square the result.

Divide $16$ by $2$ .

${(- 1 \cdot 8)}^{2}$

Multiply $- 1$ by $8$ .

${(- 8)}^{2}$

Raise $- 8$ to the power of $2$ .

$64$

Step 2

Add $64$ to get the perfect square trinomial.

$z^{2} - 16 z + 64$