Find the Perfect Square Trinomial z^2-20z

$z^{2} - 20 z$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $z$ by $2$ and square the result.

Divide $20$ by $2$ .

${(- 1 \cdot 10)}^{2}$

Multiply $- 1$ by $10$ .

${(- 10)}^{2}$

Raise $- 10$ to the power of $2$ .

$100$

Step 2

Add $100$ to get the perfect square trinomial.

$z^{2} - 20 z + 100$