Find the Perfect Square Trinomial z^2+28z

$z^{2} + 28 z$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $z$ by $2$ and square the result.

Divide $28$ by $2$ .

$14^{2}$

Raise $14$ to the power of $2$ .

$196$

Step 2

Add $196$ to get the perfect square trinomial.

$z^{2} + 28 z + 196$