Find the Perfect Square Trinomial z^2-2z

$z^{2} - 2 z$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $z$ by $2$ and square the result.

Cancel the common factor of $2$ .

Cancel the common factor.

${(- \frac{2}{2})}^{2}$

Rewrite the expression.

${(- 1 \cdot 1)}^{2}$

Simplify the expression.

Multiply $- 1$ by $1$ .

${(- 1)}^{2}$

Raise $- 1$ to the power of $2$ .

$1$

Step 2

Add $1$ to get the perfect square trinomial.

$z^{2} - 2 z + 1$