Find the Perpendicular Line 4x-y=4 and (-2,-2)

$4 x - y = 4$ and $(- 2, - 2)$

Step 1

Solve $4 x - y = 4$ .

Subtract $4 x$ from both sides of the equation.

$- y = 4 - 4 x$

Divide each term in $- y = 4 - 4 x$ by $- 1$ and simplify.

Divide each term in $- y = 4 - 4 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{4}{- 1} + \frac{- 4 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{4}{- 1} + \frac{- 4 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{4}{- 1} + \frac{- 4 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $4$ by $- 1$ .

$y = - 4 + \frac{- 4 x}{- 1}$

Move the negative one from the denominator of $\frac{- 4 x}{- 1}$ .

$y = - 4 - 1 \cdot (- 4 x)$

Rewrite $- 1 \cdot (- 4 x)$ as $- (- 4 x)$ .

$y = - 4 - (- 4 x)$

Multiply $- 4$ by $- 1$ .

$y = - 4 + 4 x$

Step 2

Find the slope when $y = - 4 + 4 x$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 4$ and $4 x$ .

$y = 4 x - 4$

Using the slope-intercept form, the slope is $4$ .

$m = 4$

Step 3

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{4}$

Step 4

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- \frac{1}{4}$ and a given point $(- 2, - 2)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (- 2) = - \frac{1}{4} \cdot (x - (- 2))$

Simplify the equation and keep it in point-slope form.

$y + 2 = - \frac{1}{4} \cdot (x + 2)$

Step 5

Write in $y = m x + b$ form.

Solve for $y$ .

Simplify $- \frac{1}{4} \cdot (x + 2)$ .

Rewrite.

$y + 2 = 0 + 0 - \frac{1}{4} \cdot (x + 2)$

Simplify by adding zeros.

$y + 2 = - \frac{1}{4} \cdot (x + 2)$

Apply the distributive property.

$y + 2 = - \frac{1}{4} x - \frac{1}{4} \cdot 2$

Combine $x$ and $\frac{1}{4}$ .

$y + 2 = - \frac{x}{4} - \frac{1}{4} \cdot 2$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{1}{4}$ into the numerator.

$y + 2 = - \frac{x}{4} + \frac{- 1}{4} \cdot 2$

Factor $2$ out of $4$ .

$y + 2 = - \frac{x}{4} + \frac{- 1}{2 (2)} \cdot 2$

Cancel the common factor.

$y + 2 = - \frac{x}{4} + \frac{- 1}{2 \cdot 2} \cdot 2$

Rewrite the expression.

$y + 2 = - \frac{x}{4} + \frac{- 1}{2}$

Move the negative in front of the fraction.

$y + 2 = - \frac{x}{4} - \frac{1}{2}$

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$y = - \frac{x}{4} - \frac{1}{2} - 2$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = - \frac{x}{4} - \frac{1}{2} - 2 \cdot \frac{2}{2}$

Combine $- 2$ and $\frac{2}{2}$ .

$y = - \frac{x}{4} - \frac{1}{2} + \frac{- 2 \cdot 2}{2}$

Combine the numerators over the common denominator.

$y = - \frac{x}{4} + \frac{- 1 - 2 \cdot 2}{2}$

Simplify the numerator.

Multiply $- 2$ by $2$ .

$y = - \frac{x}{4} + \frac{- 1 - 4}{2}$

Subtract $4$ from $- 1$ .

$y = - \frac{x}{4} + \frac{- 5}{2}$

Move the negative in front of the fraction.

$y = - \frac{x}{4} - \frac{5}{2}$

Reorder terms.

$y = - (\frac{1}{4} x) - \frac{5}{2}$

Remove parentheses.

$y = - \frac{1}{4} x - \frac{5}{2}$

Step 6

Find the Perpendicular Line 4x-y=4 and (-2,-2)

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