Find the Perpendicular Line perpendicular to y=1/2x+2/3 , passes through (2,3)

perpendicular to $y = \frac{1}{2} x + \frac{2}{3}$ , passes through $(2, 3)$

Find the slope when $y = \frac{1}{2} x + \frac{2}{3}$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $\frac{1}{2}$ and $x$ .

$y = \frac{x}{2} + \frac{2}{3}$

Reorder terms.

$y = \frac{1}{2} x + \frac{2}{3}$

Using the slope-intercept form, the slope is $\frac{1}{2}$ .

$m = \frac{1}{2}$

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{1}{2}}$

Simplify $- \frac{1}{\frac{1}{2}}$ to find the slope of the perpendicular line.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 \cdot 2)$

Multiply $2$ by $1$ .

$m_{perpendicular} = - 1 \cdot 2$

Multiply $- 1$ by $2$ .

$m_{perpendicular} = - 2$

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- 2$ and a given point $(2, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = - 2 \cdot (x - (2))$

Simplify the equation and keep it in point-slope form.

$y - 3 = - 2 \cdot (x - 2)$

Solve for $y$ .

Simplify $- 2 \cdot (x - 2)$ .

Rewrite.

$y - 3 = 0 + 0 - 2 \cdot (x - 2)$

Simplify by adding zeros.

$y - 3 = - 2 \cdot (x - 2)$

Apply the distributive property.

$y - 3 = - 2 x - 2 \cdot - 2$

Multiply $- 2$ by $- 2$ .

$y - 3 = - 2 x + 4$

Move all terms not containing $y$ to the right side of the equation.

Add $3$ to both sides of the equation.

$y = - 2 x + 4 + 3$

Add $4$ and $3$ .

$y = - 2 x + 7$

Find the Perpendicular Line perpendicular to y=1/2x+2/3 , passes through (2,3)

Related Questions

Support LCMGCF.com by disabling your adblocker.