Find the Perpendicular Line through: (0,-1) , perp. to y=-1/2x

through: $(0, - 1)$ , perp. to $y = - \frac{1}{2} x$

Find the slope when $y = - \frac{1}{2} x$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $x$ and $\frac{1}{2}$ .

$y = - \frac{x}{2}$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{1}{2} x)$

Remove parentheses.

$y = - \frac{1}{2} x$

Using the slope-intercept form, the slope is $- \frac{1}{2}$ .

$m = - \frac{1}{2}$

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{1}{2}}$

Simplify $- \frac{1}{- \frac{1}{2}}$ to find the slope of the perpendicular line.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{1}{2}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 \cdot 2$

Multiply $2$ by $1$ .

$m_{perpendicular} = - (- 1 \cdot 2)$

Multiply $- 1$ by $2$ .

$m_{perpendicular} = 2$

Multiply $- 1$ by $- 2$ .

$m_{perpendicular} = 2$

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $2$ and a given point $(0, - 1)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (- 1) = 2 \cdot (x - (0))$

Simplify the equation and keep it in point-slope form.

$y + 1 = 2 \cdot (x + 0)$

Solve for $y$ .

Add $x$ and $0$ .

$y + 1 = 2 x$

Subtract $1$ from both sides of the equation.

$y = 2 x - 1$

Find the Perpendicular Line through: (0,-1) , perp. to y=-1/2x

Related Questions

Support LCMGCF.com by disabling your adblocker.