Find the Perpendicular Line Through (-1,-2) ; perpendicular to the line 2x+7y+3=0

Through $(- 1, - 2)$ ; perpendicular to the line $2 x + 7 y + 3 = 0$

Solve $2 x + 7 y + 3 = 0$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $2 x$ from both sides of the equation.

$7 y + 3 = - 2 x$

Subtract $3$ from both sides of the equation.

$7 y = - 2 x - 3$

Divide each term in $7 y = - 2 x - 3$ by $7$ and simplify.

Divide each term in $7 y = - 2 x - 3$ by $7$ .

$\frac{7 y}{7} = \frac{- 2 x}{7} + \frac{- 3}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 y}{7} = \frac{- 2 x}{7} + \frac{- 3}{7}$

Divide $y$ by $1$ .

$y = \frac{- 2 x}{7} + \frac{- 3}{7}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{(2) x}{7} + \frac{- 3}{7}$

Move the negative in front of the fraction.

$y = - \frac{2 x}{7} - \frac{3}{7}$

Find the slope when $y = - \frac{2 x}{7} - \frac{3}{7}$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{2}{7} x) - \frac{3}{7}$

Remove parentheses.

$y = - \frac{2}{7} x - \frac{3}{7}$

Using the slope-intercept form, the slope is $- \frac{2}{7}$ .

$m = - \frac{2}{7}$

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{2}{7}}$

Simplify $- \frac{1}{- \frac{2}{7}}$ to find the slope of the perpendicular line.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{2}{7}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{2}{7}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 (\frac{7}{2})$

Multiply $\frac{7}{2}$ by $1$ .

$m_{perpendicular} = \frac{7}{2}$

Multiply $- - \frac{7}{2}$ .

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{7}{2})$

Multiply $\frac{7}{2}$ by $1$ .

$m_{perpendicular} = \frac{7}{2}$

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $\frac{7}{2}$ and a given point $(- 1, - 2)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (- 2) = \frac{7}{2} \cdot (x - (- 1))$

Simplify the equation and keep it in point-slope form.

$y + 2 = \frac{7}{2} \cdot (x + 1)$

Write in $y = m x + b$ form.

Solve for $y$ .

Simplify $\frac{7}{2} \cdot (x + 1)$ .

Rewrite.

$y + 2 = 0 + 0 + \frac{7}{2} \cdot (x + 1)$

Simplify by adding zeros.

$y + 2 = \frac{7}{2} \cdot (x + 1)$

Apply the distributive property.

$y + 2 = \frac{7}{2} x + \frac{7}{2} \cdot 1$

Combine $\frac{7}{2}$ and $x$ .

$y + 2 = \frac{7 x}{2} + \frac{7}{2} \cdot 1$

Multiply $\frac{7}{2}$ by $1$ .

$y + 2 = \frac{7 x}{2} + \frac{7}{2}$

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$y = \frac{7 x}{2} + \frac{7}{2} - 2$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = \frac{7 x}{2} + \frac{7}{2} - 2 \cdot \frac{2}{2}$

Combine $- 2$ and $\frac{2}{2}$ .

$y = \frac{7 x}{2} + \frac{7}{2} + \frac{- 2 \cdot 2}{2}$

Combine the numerators over the common denominator.

$y = \frac{7 x}{2} + \frac{7 - 2 \cdot 2}{2}$

Simplify the numerator.

Multiply $- 2$ by $2$ .

$y = \frac{7 x}{2} + \frac{7 - 4}{2}$

Subtract $4$ from $7$ .

$y = \frac{7 x}{2} + \frac{3}{2}$

Reorder terms.

$y = \frac{7}{2} x + \frac{3}{2}$

Find the Perpendicular Line Through (-1,-2) ; perpendicular to the line 2x+7y+3=0

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