Find the Perpendicular Line y=-6x-3 and (3,-3)

$y = - 6 x - 3$ and $(3, - 3)$

Step 1

Use the slope-intercept form to find the slope.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Using the slope-intercept form, the slope is $- 6$ .

$m = - 6$

Step 2

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- 6}$

Step 3

Simplify $- \frac{1}{- 6}$ to find the slope of the perpendicular line.

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{6}$

Multiply $- - \frac{1}{6}$ .

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{1}{6})$

Multiply $\frac{1}{6}$ by $1$ .

$m_{perpendicular} = \frac{1}{6}$

Step 4

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $\frac{1}{6}$ and a given point $(3, - 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (- 3) = \frac{1}{6} \cdot (x - (3))$

Simplify the equation and keep it in point-slope form.

$y + 3 = \frac{1}{6} \cdot (x - 3)$

Step 5

Write in $y = m x + b$ form.

Solve for $y$ .

Simplify $\frac{1}{6} \cdot (x - 3)$ .

Rewrite.

$y + 3 = 0 + 0 + \frac{1}{6} \cdot (x - 3)$

Simplify by adding zeros.

$y + 3 = \frac{1}{6} \cdot (x - 3)$

Apply the distributive property.

$y + 3 = \frac{1}{6} x + \frac{1}{6} \cdot - 3$

Combine $\frac{1}{6}$ and $x$ .

$y + 3 = \frac{x}{6} + \frac{1}{6} \cdot - 3$

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$y + 3 = \frac{x}{6} + \frac{1}{3 (2)} \cdot - 3$

Factor $3$ out of $- 3$ .

$y + 3 = \frac{x}{6} + \frac{1}{3 \cdot 2} \cdot (3 \cdot - 1)$

Cancel the common factor.

$y + 3 = \frac{x}{6} + \frac{1}{3 \cdot 2} \cdot (3 \cdot - 1)$

Rewrite the expression.

$y + 3 = \frac{x}{6} + \frac{1}{2} \cdot - 1$

Combine $\frac{1}{2}$ and $- 1$ .

$y + 3 = \frac{x}{6} + \frac{- 1}{2}$

Move the negative in front of the fraction.

$y + 3 = \frac{x}{6} - \frac{1}{2}$

Move all terms not containing $y$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$y = \frac{x}{6} - \frac{1}{2} - 3$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = \frac{x}{6} - \frac{1}{2} - 3 \cdot \frac{2}{2}$

Combine $- 3$ and $\frac{2}{2}$ .

$y = \frac{x}{6} - \frac{1}{2} + \frac{- 3 \cdot 2}{2}$

Combine the numerators over the common denominator.

$y = \frac{x}{6} + \frac{- 1 - 3 \cdot 2}{2}$

Simplify the numerator.

Multiply $- 3$ by $2$ .

$y = \frac{x}{6} + \frac{- 1 - 6}{2}$

Subtract $6$ from $- 1$ .

$y = \frac{x}{6} + \frac{- 7}{2}$

Move the negative in front of the fraction.

$y = \frac{x}{6} - \frac{7}{2}$

Reorder terms.

$y = \frac{1}{6} x - \frac{7}{2}$

Step 6

Find the Perpendicular Line y=-6x-3 and (3,-3)

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