Find the Point-Slope Form y=3x+1

$y = 3 x + 1$

Using slope-intercept form $y = m x + b$ , identify the slope $m$ .

$y = 3 x + 1$

$m = 3$

Pick any $x$ -value, then substitute into the equation and simplify to find a point on the line.

Substitute $1$ for $x$ .

$y = 3 \cdot 1 + 1$

Multiply $3$ by $1$ .

$y = 3 + 1$

Add $3$ and $1$ .

$y = 4$

Since $y = 4$ when $x = 1$ , $(1, 4)$ is a point on the line.

$(1, 4)$

Plug in the values of the found point and the value of the slope into the point-slope form $y - y_{1} = m (x - x_{1})$ .

$y - 4 = 3 (x - 1)$