Find the Points of Intersection x+2y=-1 2x+4y=-2

$x + 2 y = - 1$ $2 x + 4 y = - 2$

Subtract $2 y$ from both sides of the equation.

$x = - 1 - 2 y$

$2 x + 4 y = - 2$

Replace all occurrences of $x$ with $- 1 - 2 y$ in each equation.

Replace all occurrences of $x$ in $2 x + 4 y = - 2$ with $- 1 - 2 y$ .

$2 (- 1 - 2 y) + 4 y = - 2$

$x = - 1 - 2 y$

Simplify the left side.

Simplify $2 (- 1 - 2 y) + 4 y$ .

Simplify each term.

Apply the distributive property.

$2 \cdot - 1 + 2 (- 2 y) + 4 y = - 2$

$x = - 1 - 2 y$

Multiply $2$ by $- 1$ .

$- 2 + 2 (- 2 y) + 4 y = - 2$

$x = - 1 - 2 y$

Multiply $- 2$ by $2$ .

$- 2 - 4 y + 4 y = - 2$

$x = - 1 - 2 y$

$- 2 - 4 y + 4 y = - 2$

$x = - 1 - 2 y$

Combine the opposite terms in $- 2 - 4 y + 4 y$ .

Add $- 4 y$ and $4 y$ .

$- 2 + 0 = - 2$

$x = - 1 - 2 y$

Add $- 2$ and $0$ .

$- 2 = - 2$

$x = - 1 - 2 y$

$- 2 = - 2$

$x = - 1 - 2 y$

$- 2 = - 2$

$x = - 1 - 2 y$

$- 2 = - 2$

$x = - 1 - 2 y$

$- 2 = - 2$

$x = - 1 - 2 y$

Remove any equations from the system that are always true.

$x = - 1 - 2 y$

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