Find the Position Vector (1,4) , (13,6)

$(1, 4)$ , $(13, 6)$

Step 1

To find the position vector, subtract the initial point vector $P$ from the terminal point vector $Q$ .

$Q - P = (13 i + 6 j) - (1 i + 4 j)$

Step 2

Simplify each term.

Multiply $i$ by $1$ .

$13 i + 6 j - (i + 4 j)$

Apply the distributive property.

$13 i + 6 j - i - (4 j)$

Multiply $4$ by $- 1$ .

$13 i + 6 j - i - 4 j$

Step 3

Simplify by adding terms.

Subtract $i$ from $13 i$ .

$6 j + 12 i - 4 j$

Subtract $4 j$ from $6 j$ .

$2 j + 12 i$

Step 4