Find the Product (2x-5)^3

${(2 x - 5)}^{3}$

Step 1

Use the Binomial Theorem.

${(2 x)}^{3} + 3 {(2 x)}^{2} \cdot - 5 + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Step 2

Simplify each term.

Apply the product rule to $2 x$ .

$2^{3} x^{3} + 3 {(2 x)}^{2} \cdot - 5 + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Raise $2$ to the power of $3$ .

$8 x^{3} + 3 {(2 x)}^{2} \cdot - 5 + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Apply the product rule to $2 x$ .

$8 x^{3} + 3 (2^{2} x^{2}) \cdot - 5 + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Raise $2$ to the power of $2$ .

$8 x^{3} + 3 (4 x^{2}) \cdot - 5 + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Multiply $4$ by $3$ .

$8 x^{3} + 12 x^{2} \cdot - 5 + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Multiply $- 5$ by $12$ .

$8 x^{3} - 60 x^{2} + 3 (2 x) {(- 5)}^{2} + {(- 5)}^{3}$

Multiply $2$ by $3$ .

$8 x^{3} - 60 x^{2} + 6 x {(- 5)}^{2} + {(- 5)}^{3}$

Raise $- 5$ to the power of $2$ .

$8 x^{3} - 60 x^{2} + 6 x \cdot 25 + {(- 5)}^{3}$

Multiply $25$ by $6$ .

$8 x^{3} - 60 x^{2} + 150 x + {(- 5)}^{3}$

Raise $- 5$ to the power of $3$ .

$8 x^{3} - 60 x^{2} + 150 x - 125$