Find the Product 2x(x^2+x-5)

$2 x (x^{2} + x - 5)$

Step 1

Apply the distributive property.

$2 x \cdot x^{2} + 2 x \cdot x + 2 x \cdot - 5$

Step 2

Simplify.

Multiply $x$ by $x^{2}$ by adding the exponents.

Move $x^{2}$ .

$2 (x^{2} x) + 2 x \cdot x + 2 x \cdot - 5$

Multiply $x^{2}$ by $x$ .

Raise $x$ to the power of $1$ .

$2 (x^{2} x^{1}) + 2 x \cdot x + 2 x \cdot - 5$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 x^{2 + 1} + 2 x \cdot x + 2 x \cdot - 5$

Add $2$ and $1$ .

$2 x^{3} + 2 x \cdot x + 2 x \cdot - 5$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$2 x^{3} + 2 (x \cdot x) + 2 x \cdot - 5$

Multiply $x$ by $x$ .

$2 x^{3} + 2 x^{2} + 2 x \cdot - 5$

Multiply $- 5$ by $2$ .

$2 x^{3} + 2 x^{2} - 10 x$