Find the Product (3x-2)^3

${(3 x - 2)}^{3}$

Use the Binomial Theorem.

${(3 x)}^{3} + 3 {(3 x)}^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Simplify each term.

Apply the product rule to $3 x$ .

$3^{3} x^{3} + 3 {(3 x)}^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Raise $3$ to the power of $3$ .

$27 x^{3} + 3 {(3 x)}^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Apply the product rule to $3 x$ .

$27 x^{3} + 3 (3^{2} x^{2}) \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Multiply $3$ by $3^{2}$ by adding the exponents.

Move $3^{2}$ .

$27 x^{3} + 3^{2} \cdot 3 x^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Multiply $3^{2}$ by $3$ .

Raise $3$ to the power of $1$ .

$27 x^{3} + 3^{2} \cdot 3^{1} x^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$27 x^{3} + 3^{2 + 1} x^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Add $2$ and $1$ .

$27 x^{3} + 3^{3} x^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Raise $3$ to the power of $3$ .

$27 x^{3} + 27 x^{2} \cdot - 2 + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Multiply $- 2$ by $27$ .

$27 x^{3} - 54 x^{2} + 3 (3 x) {(- 2)}^{2} + {(- 2)}^{3}$

Multiply $3$ by $3$ .

$27 x^{3} - 54 x^{2} + 9 x {(- 2)}^{2} + {(- 2)}^{3}$

Raise $- 2$ to the power of $2$ .

$27 x^{3} - 54 x^{2} + 9 x \cdot 4 + {(- 2)}^{3}$

Multiply $4$ by $9$ .

$27 x^{3} - 54 x^{2} + 36 x + {(- 2)}^{3}$

Raise $- 2$ to the power of $3$ .

$27 x^{3} - 54 x^{2} + 36 x - 8$