Find the Product -4(3/4e+2)=7+1/2e-8

$- 4 (\frac{3}{4} e + 2) = 7 + \frac{1}{2} e - 8$

Step 1

Combine $\frac{3}{4}$ and $e$ .

$- 4 (\frac{3 e}{4} + 2) = 7 + \frac{1}{2} \cdot e - 8$

Step 2

Simplify terms.

Apply the distributive property.

$- 4 \frac{3 e}{4} - 4 \cdot 2 = 7 + \frac{1}{2} \cdot e - 8$

Cancel the common factor of $4$ .

Factor $4$ out of $- 4$ .

$4 (- 1) \frac{3 e}{4} - 4 \cdot 2 = 7 + \frac{1}{2} \cdot e - 8$

Cancel the common factor.

$4 \cdot - 1 \frac{3 e}{4} - 4 \cdot 2 = 7 + \frac{1}{2} \cdot e - 8$

Rewrite the expression.

$- 1 (3 e) - 4 \cdot 2 = 7 + \frac{1}{2} \cdot e - 8$

Multiply.

Multiply $3$ by $- 1$ .

$- 3 e - 4 \cdot 2 = 7 + \frac{1}{2} \cdot e - 8$

Multiply $- 4$ by $2$ .

$- 3 e - 8 = 7 + \frac{1}{2} \cdot e - 8$

Step 3

Combine $\frac{1}{2}$ and $e$ .

$- 3 e - 8 = 7 + \frac{e}{2} - 8$

Step 4

Subtract $8$ from $7$ .

$- 3 e - 8 = - 1 + \frac{e}{2}$