Find the Product f(x)=x^3 , g(x)=x-1

$f (x) = x^{3}$ , $g (x) = x - 1$

Step 1

Replace the function designators with the actual functions in $f (x) \cdot (g (x))$ .

$(x^{3}) \cdot (x - 1)$

Step 2

Simplify.

Apply the distributive property.

$x^{3} x + x^{3} \cdot - 1$

Multiply $x^{3}$ by $x$ by adding the exponents.

Multiply $x^{3}$ by $x$ .

Raise $x$ to the power of $1$ .

$x^{3} x^{1} + x^{3} \cdot - 1$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{3 + 1} + x^{3} \cdot - 1$

Add $3$ and $1$ .

$x^{4} + x^{3} \cdot - 1$

Move $- 1$ to the left of $x^{3}$ .

$x^{4} - 1 \cdot x^{3}$

Rewrite $- 1 x^{3}$ as $- x^{3}$ .

$x^{4} - x^{3}$