Find the Product (x-6)^3

${(x - 6)}^{3}$

Use the Binomial Theorem.

$x^{3} + 3 x^{2} \cdot - 6 + 3 x {(- 6)}^{2} + {(- 6)}^{3}$

Simplify each term.

Multiply $- 6$ by $3$ .

$x^{3} - 18 x^{2} + 3 x {(- 6)}^{2} + {(- 6)}^{3}$

Raise $- 6$ to the power of $2$ .

$x^{3} - 18 x^{2} + 3 x \cdot 36 + {(- 6)}^{3}$

Multiply $36$ by $3$ .

$x^{3} - 18 x^{2} + 108 x + {(- 6)}^{3}$

Raise $- 6$ to the power of $3$ .

$x^{3} - 18 x^{2} + 108 x - 216$