Find the Quadratic Equation (0,-3/2)

$(0, - \frac{3}{2})$

$x = 0$ and $x = - \frac{3}{2}$ are the two real distinct solutions for the quadratic equation, which means that $x - 0$ and $x + \frac{3}{2}$ are the factors of the quadratic equation.

$(x - 0) (x + \frac{3}{2}) = 0$

Simplify terms.

Subtract $0$ from $x$ .

$x (x + \frac{3}{2}) = 0$

Apply the distributive property.

$x \cdot x + x (\frac{3}{2}) = 0$

Multiply $x$ by $x$ .

$x^{2} + x (\frac{3}{2}) = 0$

Combine $x$ and $\frac{3}{2}$ .

$x^{2} + \frac{x \cdot 3}{2} = 0$

Move $3$ to the left of $x$ .

$x^{2} + \frac{3 x}{2} = 0$

The standard quadratic equation using the given set of solutions ${0, - \frac{3}{2}}$ is $y = x^{2} + \frac{3 x}{2}$ .

$y = x^{2} + \frac{3 x}{2}$

Find the Quadratic Equation (0,-3/2)

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