Find the Quadratic Equation (5,-3)

$(5, - 3)$

Step 1

$x = 5$ and $x = - 3$ are the two real distinct solutions for the quadratic equation, which means that $x - 5$ and $x + 3$ are the factors of the quadratic equation.

$(x - 5) (x + 3) = 0$

Step 2

Expand $(x - 5) (x + 3)$ using the FOIL Method.

Apply the distributive property.

$x (x + 3) - 5 (x + 3) = 0$

Apply the distributive property.

$x \cdot x + x \cdot 3 - 5 (x + 3) = 0$

Apply the distributive property.

$x \cdot x + x \cdot 3 - 5 x - 5 \cdot 3 = 0$

Step 3

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 3 - 5 x - 5 \cdot 3 = 0$

Move $3$ to the left of $x$ .

$x^{2} + 3 \cdot x - 5 x - 5 \cdot 3 = 0$

Multiply $- 5$ by $3$ .

$x^{2} + 3 x - 5 x - 15 = 0$

Subtract $5 x$ from $3 x$ .

$x^{2} - 2 x - 15 = 0$

Step 4

The standard quadratic equation using the given set of solutions ${5, - 3}$ is $y = x^{2} - 2 x - 15$ .

$y = x^{2} - 2 x - 15$

Step 5

Find the Quadratic Equation (5,-3)

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