Find the Reciprocal square root of 75

$\sqrt{75}$

To find the reciprocal, divide $1$ by the number given.

$\frac{1}{\sqrt{75}}$

Simplify.

Simplify the denominator.

Rewrite $75$ as $5^{2} \cdot 3$ .

Factor $25$ out of $75$ .

$\frac{1}{\sqrt{25 (3)}}$

Rewrite $25$ as $5^{2}$ .

$\frac{1}{\sqrt{5^{2} \cdot 3}}$

Pull terms out from under the radical.

$\frac{1}{5 \sqrt{3}}$

Multiply $\frac{1}{5 \sqrt{3}}$ by $\frac{\sqrt{3}}{\sqrt{3}}$ .

$\frac{1}{5 \sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$

Combine and simplify the denominator.

Multiply $\frac{1}{5 \sqrt{3}}$ by $\frac{\sqrt{3}}{\sqrt{3}}$ .

$\frac{\sqrt{3}}{5 \sqrt{3} \sqrt{3}}$

Move $\sqrt{3}$ .

$\frac{\sqrt{3}}{5 (\sqrt{3} \sqrt{3})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{\sqrt{3}}{5 ({\sqrt{3}}^{1} \sqrt{3})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{\sqrt{3}}{5 ({\sqrt{3}}^{1} {\sqrt{3}}^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sqrt{3}}{5 {\sqrt{3}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{\sqrt{3}}{5 {\sqrt{3}}^{2}}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{\sqrt{3}}{5 {(3^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{\sqrt{3}}{5 \cdot 3^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{\sqrt{3}}{5 \cdot 3^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{\sqrt{3}}{5 \cdot 3^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{\sqrt{3}}{5 \cdot 3^{1}}$

Evaluate the exponent.

$\frac{\sqrt{3}}{5 \cdot 3}$

Multiply $5$ by $3$ .

$\frac{\sqrt{3}}{15}$

The result can be shown in multiple forms.

Exact Form:

$\frac{\sqrt{3}}{15}$

Decimal Form:

$0.11547005 \dots$

Find the Reciprocal square root of 75

Related Questions

Support LCMGCF.com by disabling your adblocker.