Find the Remainder (-19x^2+3+7x+15x^4)÷(-5x^2+3)

$(- 19 x^{2} + 3 + 7 x + 15 x^{4}) \div (- 5 x^{2} + 3)$

To calculate the remainder, first divide the polynomials.

Expand $- 19 x^{2} + 3 + 7 x + 15 x^{4}$ .

Move $3$ .

$\frac{- 19 x^{2} + 7 x + 3 + 15 x^{4}}{- 5 x^{2} + 3}$

Move $3$ .

$\frac{- 19 x^{2} + 7 x + 15 x^{4} + 3}{- 5 x^{2} + 3}$

Move $7 x$ .

$\frac{- 19 x^{2} + 15 x^{4} + 7 x + 3}{- 5 x^{2} + 3}$

Reorder $- 19 x^{2}$ and $15 x^{4}$ .

$\frac{15 x^{4} - 19 x^{2} + 7 x + 3}{- 5 x^{2} + 3}$

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

Divide the highest order term in the dividend $15 x^{4}$ by the highest order term in divisor $- 5 x^{2}$ .

$3 x^{2}$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

Multiply the new quotient term by the divisor.

$3 x^{2}$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $15 x^{4} + 0 - 9 x^{2}$

$3 x^{2}$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$3 x^{2}$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

$10 x^{2}$

Pull the next term from the original dividend down into the current dividend.

$3 x^{2}$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

$10 x^{2}$

$7 x$

$3$

Divide the highest order term in the dividend $- 10 x^{2}$ by the highest order term in divisor $- 5 x^{2}$ .

$3 x^{2}$

$0 x$

$2$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

$10 x^{2}$

$7 x$

$3$

Multiply the new quotient term by the divisor.

$3 x^{2}$

$0 x$

$2$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

$10 x^{2}$

$7 x$

$3$

$10 x^{2}$

$0$

$6$

The expression needs to be subtracted from the dividend, so change all the signs in $- 10 x^{2} + 0 + 6$

$3 x^{2}$

$0 x$

$2$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

$10 x^{2}$

$7 x$

$3$

$10 x^{2}$

$0$

$6$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$3 x^{2}$

$0 x$

$2$

$5 x^{2}$

$0 x$

$3$

$15 x^{4}$

$0 x^{3}$

$19 x^{2}$

$7 x$

$3$

$15 x^{4}$

$0$

$9 x^{2}$

$10 x^{2}$

$7 x$

$3$

$10 x^{2}$

$0$

$6$

$7 x$

$3$

The final answer is the quotient plus the remainder over the divisor.

$- 3 x^{2} + 2 + \frac{7 x - 3}{- 5 x^{2} + 3}$

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$7 x - 3$

Find the Remainder (-19x^2+3+7x+15x^4)÷(-5x^2+3)

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