Find the Remainder (-4x^4+3x^2+12-11x^3)÷(-x^2-2x+3)

$(- 4 x^{4} + 3 x^{2} + 12 - 11 x^{3}) \div (- x^{2} - 2 x + 3)$

Step 1

To calculate the remainder, first divide the polynomials.

Expand $- 4 x^{4} + 3 x^{2} + 12 - 11 x^{3}$ .

Move $12$ .

$\frac{- 4 x^{4} + 3 x^{2} - 11 x^{3} + 12}{- x^{2} - 2 x + 3}$

Move $3 x^{2}$ .

$\frac{- 4 x^{4} - 11 x^{3} + 3 x^{2} + 12}{- x^{2} - 2 x + 3}$

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

Divide the highest order term in the dividend $- 4 x^{4}$ by the highest order term in divisor $- x^{2}$ .

$4 x^{2}$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

Multiply the new quotient term by the divisor.

$4 x^{2}$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $- 4 x^{4} - 8 x^{3} + 12 x^{2}$

$4 x^{2}$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$4 x^{2}$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

Pull the next terms from the original dividend down into the current dividend.

$4 x^{2}$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

Divide the highest order term in the dividend $- 3 x^{3}$ by the highest order term in divisor $- x^{2}$ .

$4 x^{2}$

$3 x$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

Multiply the new quotient term by the divisor.

$4 x^{2}$

$3 x$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x^{3} - 6 x^{2} + 9 x$

$4 x^{2}$

$3 x$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$4 x^{2}$

$3 x$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

$3 x^{2}$

$9 x$

Pull the next terms from the original dividend down into the current dividend.

$4 x^{2}$

$3 x$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

$3 x^{2}$

$9 x$

$12$

Divide the highest order term in the dividend $- 3 x^{2}$ by the highest order term in divisor $- x^{2}$ .

$4 x^{2}$

$3 x$

$3$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

$3 x^{2}$

$9 x$

$12$

Multiply the new quotient term by the divisor.

$4 x^{2}$

$3 x$

$3$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

$3 x^{2}$

$9 x$

$12$

$3 x^{2}$

$6 x$

$9$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x^{2} - 6 x + 9$

$4 x^{2}$

$3 x$

$3$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

$3 x^{2}$

$9 x$

$12$

$3 x^{2}$

$6 x$

$9$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$4 x^{2}$

$3 x$

$3$

$x^{2}$

$2 x$

$3$

$4 x^{4}$

$11 x^{3}$

$3 x^{2}$

$0 x$

$12$

$4 x^{4}$

$8 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$0 x$

$3 x^{3}$

$6 x^{2}$

$9 x$

$3 x^{2}$

$9 x$

$12$

$3 x^{2}$

$6 x$

$9$

$3 x$

$3$

The final answer is the quotient plus the remainder over the divisor.

$4 x^{2} + 3 x + 3 + \frac{- 3 x + 3}{- x^{2} - 2 x + 3}$

Step 2

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$- 3 x + 3$

Find the Remainder (-4x^4+3x^2+12-11x^3)÷(-x^2-2x+3)

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