Find the Remainder (-7x^4+20x^2+10+5x^3)÷(-x^2+x+3)

$(- 7 x^{4} + 20 x^{2} + 10 + 5 x^{3}) \div (- x^{2} + x + 3)$

Step 1

To calculate the remainder, first divide the polynomials.

Expand $- 7 x^{4} + 20 x^{2} + 10 + 5 x^{3}$ .

Move $10$ .

$\frac{- 7 x^{4} + 20 x^{2} + 5 x^{3} + 10}{- x^{2} + x + 3}$

Move $20 x^{2}$ .

$\frac{- 7 x^{4} + 5 x^{3} + 20 x^{2} + 10}{- x^{2} + x + 3}$

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

Divide the highest order term in the dividend $- 7 x^{4}$ by the highest order term in divisor $- x^{2}$ .

$7 x^{2}$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

Multiply the new quotient term by the divisor.

$7 x^{2}$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $- 7 x^{4} + 7 x^{3} + 21 x^{2}$

$7 x^{2}$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$7 x^{2}$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

Pull the next terms from the original dividend down into the current dividend.

$7 x^{2}$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

Divide the highest order term in the dividend $- 2 x^{3}$ by the highest order term in divisor $- x^{2}$ .

$7 x^{2}$

$2 x$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

Multiply the new quotient term by the divisor.

$7 x^{2}$

$2 x$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

The expression needs to be subtracted from the dividend, so change all the signs in $- 2 x^{3} + 2 x^{2} + 6 x$

$7 x^{2}$

$2 x$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$7 x^{2}$

$2 x$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

$3 x^{2}$

$6 x$

Pull the next terms from the original dividend down into the current dividend.

$7 x^{2}$

$2 x$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

$3 x^{2}$

$6 x$

$10$

Divide the highest order term in the dividend $- 3 x^{2}$ by the highest order term in divisor $- x^{2}$ .

$7 x^{2}$

$2 x$

$3$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

$3 x^{2}$

$6 x$

$10$

Multiply the new quotient term by the divisor.

$7 x^{2}$

$2 x$

$3$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

$3 x^{2}$

$6 x$

$10$

$3 x^{2}$

$3 x$

$9$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x^{2} + 3 x + 9$

$7 x^{2}$

$2 x$

$3$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

$3 x^{2}$

$6 x$

$10$

$3 x^{2}$

$3 x$

$9$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$7 x^{2}$

$2 x$

$3$

$x^{2}$

$x$

$3$

$7 x^{4}$

$5 x^{3}$

$20 x^{2}$

$0 x$

$10$

$7 x^{4}$

$7 x^{3}$

$21 x^{2}$

$2 x^{3}$

$x^{2}$

$0 x$

$2 x^{3}$

$2 x^{2}$

$6 x$

$3 x^{2}$

$6 x$

$10$

$3 x^{2}$

$3 x$

$9$

$9 x$

$1$

The final answer is the quotient plus the remainder over the divisor.

$7 x^{2} + 2 x + 3 + \frac{- 9 x + 1}{- x^{2} + x + 3}$

Step 2

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$- 9 x + 1$

Find the Remainder (-7x^4+20x^2+10+5x^3)÷(-x^2+x+3)

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