Find the Remainder (x^4-12x^2-5)÷(x+3)

$(x^{4} - 12 x^{2} - 5) \div (x + 3)$

To calculate the remainder, first divide the polynomials.

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

Divide the highest order term in the dividend $x^{4}$ by the highest order term in divisor $x$ .

$x^{3}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

Multiply the new quotient term by the divisor.

$x^{3}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

The expression needs to be subtracted from the dividend, so change all the signs in $x^{4} + 3 x^{3}$

$x^{3}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{3}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

Pull the next terms from the original dividend down into the current dividend.

$x^{3}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

Divide the highest order term in the dividend $- 3 x^{3}$ by the highest order term in divisor $x$ .

$x^{3}$

$3 x^{2}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

Multiply the new quotient term by the divisor.

				$x^{3}$	-	$3 x^{2}$
$x$	+	$3$		$x^{4}$	+	$0 x^{3}$	-	$12 x^{2}$	+	$0 x$	-	$5$
			-	$x^{4}$	-	$3 x^{3}$
					-	$3 x^{3}$	-	$12 x^{2}$
					-	$3 x^{3}$	-	$9 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x^{3} - 9 x^{2}$

$x^{3}$

$3 x^{2}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{3}$

$3 x^{2}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

Pull the next terms from the original dividend down into the current dividend.

$x^{3}$

$3 x^{2}$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

Divide the highest order term in the dividend $- 3 x^{2}$ by the highest order term in divisor $x$ .

$x^{3}$

$3 x^{2}$

$3 x$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

Multiply the new quotient term by the divisor.

$x^{3}$

$3 x^{2}$

$3 x$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x^{2} - 9 x$

$x^{3}$

$3 x^{2}$

$3 x$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{3}$

$3 x^{2}$

$3 x$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

Pull the next terms from the original dividend down into the current dividend.

$x^{3}$

$3 x^{2}$

$3 x$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

$5$

Divide the highest order term in the dividend $9 x$ by the highest order term in divisor $x$ .

$x^{3}$

$3 x^{2}$

$3 x$

$9$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

$5$

Multiply the new quotient term by the divisor.

$x^{3}$

$3 x^{2}$

$3 x$

$9$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

$5$

$9 x$

$27$

The expression needs to be subtracted from the dividend, so change all the signs in $9 x + 27$

$x^{3}$

$3 x^{2}$

$3 x$

$9$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

$5$

$9 x$

$27$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{3}$

$3 x^{2}$

$3 x$

$9$

$x$

$3$

$x^{4}$

$0 x^{3}$

$12 x^{2}$

$0 x$

$5$

$x^{4}$

$3 x^{3}$

$12 x^{2}$

$3 x^{3}$

$9 x^{2}$

$3 x^{2}$

$0 x$

$3 x^{2}$

$9 x$

$5$

$9 x$

$27$

$32$

The final answer is the quotient plus the remainder over the divisor.

$x^{3} - 3 x^{2} - 3 x + 9 - \frac{32}{x + 3}$

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$- 32$

Find the Remainder (x^4-12x^2-5)÷(x+3)

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