Find the Remainder (x^5-15x^4+90x^3-270^2+405x-243)÷(x-3)

$(x^{5} - 15 x^{4} + 90 x^{3} - 270^{2} + 405 x - 243) \div (x - 3)$

To calculate the remainder, first divide the polynomials.

Expand $x^{5} - 15 x^{4} + 90 x^{3} - 270^{2} + 405 x - 243$ .

Rewrite the exponentiation as a product.

$\frac{x^{5} - 15 x^{4} + 90 x^{3} - (270 \cdot 270) + 405 x - 243}{x - 3}$

Remove parentheses.

$\frac{x^{5} - 15 x^{4} + 90 x^{3} - 1 \cdot 270 \cdot 270 + 405 x - 243}{x - 3}$

Multiply $- 1$ by $270$ .

$\frac{x^{5} - 15 x^{4} + 90 x^{3} - 270 \cdot 270 + 405 x - 243}{x - 3}$

Multiply $- 270$ by $270$ .

$\frac{x^{5} - 15 x^{4} + 90 x^{3} - 72900 + 405 x - 243}{x - 3}$

Move $- 72900$ .

$\frac{x^{5} - 15 x^{4} + 90 x^{3} + 405 x - 72900 - 243}{x - 3}$

Subtract $243$ from $- 72900$ .

$\frac{x^{5} - 15 x^{4} + 90 x^{3} + 405 x - 73143}{x - 3}$

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

Divide the highest order term in the dividend $x^{5}$ by the highest order term in divisor $x$ .

$x^{4}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

Multiply the new quotient term by the divisor.

$x^{4}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

The expression needs to be subtracted from the dividend, so change all the signs in $x^{5} - 3 x^{4}$

$x^{4}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{4}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

Pull the next terms from the original dividend down into the current dividend.

$x^{4}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

Divide the highest order term in the dividend $- 12 x^{4}$ by the highest order term in divisor $x$ .

$x^{4}$

$12 x^{3}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

Multiply the new quotient term by the divisor.

$x^{4}$

$12 x^{3}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

The expression needs to be subtracted from the dividend, so change all the signs in $- 12 x^{4} + 36 x^{3}$

$x^{4}$

$12 x^{3}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{4}$

$12 x^{3}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

Pull the next terms from the original dividend down into the current dividend.

$x^{4}$

$12 x^{3}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

Divide the highest order term in the dividend $54 x^{3}$ by the highest order term in divisor $x$ .

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

Multiply the new quotient term by the divisor.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $54 x^{3} - 162 x^{2}$

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

Pull the next terms from the original dividend down into the current dividend.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

Divide the highest order term in the dividend $162 x^{2}$ by the highest order term in divisor $x$ .

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

Multiply the new quotient term by the divisor.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

The expression needs to be subtracted from the dividend, so change all the signs in $162 x^{2} - 486 x$

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

$891 x$

Pull the next terms from the original dividend down into the current dividend.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

$891 x$

$73143$

Divide the highest order term in the dividend $891 x$ by the highest order term in divisor $x$ .

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$891$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

$891 x$

$73143$

Multiply the new quotient term by the divisor.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$891$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

$891 x$

$73143$

$891 x$

$2673$

The expression needs to be subtracted from the dividend, so change all the signs in $891 x - 2673$

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$891$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

$891 x$

$73143$

$891 x$

$2673$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x^{4}$

$12 x^{3}$

$54 x^{2}$

$162 x$

$891$

$x$

$3$

$x^{5}$

$15 x^{4}$

$90 x^{3}$

$0 x^{2}$

$405 x$

$73143$

$x^{5}$

$3 x^{4}$

$12 x^{4}$

$90 x^{3}$

$12 x^{4}$

$36 x^{3}$

$54 x^{3}$

$0 x^{2}$

$54 x^{3}$

$162 x^{2}$

$405 x$

$162 x^{2}$

$486 x$

$891 x$

$73143$

$891 x$

$2673$

$70470$

The final answer is the quotient plus the remainder over the divisor.

$x^{4} - 12 x^{3} + 54 x^{2} + 162 x + 891 - \frac{70470}{x - 3}$

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$- 70470$

Find the Remainder (x^5-15x^4+90x^3-270^2+405x-243)÷(x-3)

Related Questions

Support LCMGCF.com by disabling your adblocker.