Find the Roots (Zeros) 0=9x^2-49

$0 = 9 x^{2} - 49$

Rewrite the equation as $9 x^{2} - 49 = 0$ .

$9 x^{2} - 49 = 0$

Add $49$ to both sides of the equation.

$9 x^{2} = 49$

Divide each term in $9 x^{2} = 49$ by $9$ and simplify.

Divide each term in $9 x^{2} = 49$ by $9$ .

$\frac{9 x^{2}}{9} = \frac{49}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x^{2}}{9} = \frac{49}{9}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{49}{9}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{49}{9}}$

Simplify $\pm \sqrt{\frac{49}{9}}$ .

Rewrite $\sqrt{\frac{49}{9}}$ as $\frac{\sqrt{49}}{\sqrt{9}}$ .

$x = \pm \frac{\sqrt{49}}{\sqrt{9}}$

Simplify the numerator.

Rewrite $49$ as $7^{2}$ .

$x = \pm \frac{\sqrt{7^{2}}}{\sqrt{9}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{7}{\sqrt{9}}$

Simplify the denominator.

Rewrite $9$ as $3^{2}$ .

$x = \pm \frac{7}{\sqrt{3^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{7}{3}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{7}{3}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{7}{3}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{7}{3}, - \frac{7}{3}$