Find the Roots (Zeros) 3x^2-3=0

$3 x^{2} - 3 = 0$

Add $3$ to both sides of the equation.

$3 x^{2} = 3$

Divide each term in $3 x^{2} = 3$ by $3$ and simplify.

Divide each term in $3 x^{2} = 3$ by $3$ .

$\frac{3 x^{2}}{3} = \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x^{2}}{3} = \frac{3}{3}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$x^{2} = 1$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{1}$

Any root of $1$ is $1$ .

$x = \pm 1$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 1$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 1$