Find the Roots (Zeros) -4x^4+8x^3+60x^2

$- 4 x^{4} + 8 x^{3} + 60 x^{2}$

Step 1

Set $- 4 x^{4} + 8 x^{3} + 60 x^{2}$ equal to $0$ .

$- 4 x^{4} + 8 x^{3} + 60 x^{2} = 0$

Step 2

Solve for $x$ .

Factor the left side of the equation.

Factor $- 4 x^{2}$ out of $- 4 x^{4} + 8 x^{3} + 60 x^{2}$ .

Factor $- 4 x^{2}$ out of $- 4 x^{4}$ .

$- 4 x^{2} x^{2} + 8 x^{3} + 60 x^{2} = 0$

Factor $- 4 x^{2}$ out of $8 x^{3}$ .

$- 4 x^{2} x^{2} - 4 x^{2} (- 2 x) + 60 x^{2} = 0$

Factor $- 4 x^{2}$ out of $60 x^{2}$ .

$- 4 x^{2} x^{2} - 4 x^{2} (- 2 x) - 4 x^{2} \cdot - 15 = 0$

Factor $- 4 x^{2}$ out of $- 4 x^{2} (x^{2}) - 4 x^{2} (- 2 x)$ .

$- 4 x^{2} (x^{2} - 2 x) - 4 x^{2} \cdot - 15 = 0$

Factor $- 4 x^{2}$ out of $- 4 x^{2} (x^{2} - 2 x) - 4 x^{2} (- 15)$ .

$- 4 x^{2} (x^{2} - 2 x - 15) = 0$

Factor.

Factor $x^{2} - 2 x - 15$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 15$ and whose sum is $- 2$ .

$- 5, 3$

Write the factored form using these integers.

$- 4 x^{2} ((x - 5) (x + 3)) = 0$

Remove unnecessary parentheses.

$- 4 x^{2} (x - 5) (x + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{2} = 0$

$x - 5 = 0$

$x + 3 = 0$

Set $x^{2}$ equal to $0$ and solve for $x$ .

Set $x^{2}$ equal to $0$ .

$x^{2} = 0$

Solve $x^{2} = 0$ for $x$ .

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Plus or minus $0$ is $0$ .

$x = 0$

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $- 4 x^{2} (x - 5) (x + 3) = 0$ true.

$x = 0, 5, - 3$

Step 3

Find the Roots (Zeros) -4x^4+8x^3+60x^2

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