Find the Roots (Zeros) 7x^4=56

$7 x^{4} = 56$

Divide each term in $7 x^{4} = 56$ by $7$ and simplify.

Divide each term in $7 x^{4} = 56$ by $7$ .

$\frac{7 x^{4}}{7} = \frac{56}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x^{4}}{7} = \frac{56}{7}$

Divide $x^{4}$ by $1$ .

$x^{4} = \frac{56}{7}$

Simplify the right side.

Divide $56$ by $7$ .

$x^{4} = 8$

Take the 4th root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt[4]{8}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \sqrt[4]{8}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \sqrt[4]{8}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt[4]{8}, - \sqrt[4]{8}$

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt[4]{8}, - \sqrt[4]{8}$

Decimal Form:

$x = 1.68179283 \dots, - 1.68179283 \dots$