Find the Roots (Zeros) 8(x-2)^3=0

$8 {(x - 2)}^{3} = 0$

Divide each term in $8 {(x - 2)}^{3} = 0$ by $8$ and simplify.

Divide each term in $8 {(x - 2)}^{3} = 0$ by $8$ .

$\frac{8 {(x - 2)}^{3}}{8} = \frac{0}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 {(x - 2)}^{3}}{8} = \frac{0}{8}$

Divide ${(x - 2)}^{3}$ by $1$ .

${(x - 2)}^{3} = \frac{0}{8}$

Simplify the right side.

Divide $0$ by $8$ .

${(x - 2)}^{3} = 0$

Set the $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$