Find the Roots (Zeros) (9x+7)(4x+1)(3x+4)=0

$(9 x + 7) (4 x + 1) (3 x + 4) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$9 x + 7 = 0$

$4 x + 1 = 0$

$3 x + 4 = 0$

Set $9 x + 7$ equal to $0$ and solve for $x$ .

Set $9 x + 7$ equal to $0$ .

$9 x + 7 = 0$

Solve $9 x + 7 = 0$ for $x$ .

Subtract $7$ from both sides of the equation.

$9 x = - 7$

Divide each term in $9 x = - 7$ by $9$ and simplify.

Divide each term in $9 x = - 7$ by $9$ .

$\frac{9 x}{9} = \frac{- 7}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{- 7}{9}$

Divide $x$ by $1$ .

$x = \frac{- 7}{9}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{7}{9}$

Set $4 x + 1$ equal to $0$ and solve for $x$ .

Set $4 x + 1$ equal to $0$ .

$4 x + 1 = 0$

Solve $4 x + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$4 x = - 1$

Divide each term in $4 x = - 1$ by $4$ and simplify.

Divide each term in $4 x = - 1$ by $4$ .

$\frac{4 x}{4} = \frac{- 1}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 1}{4}$

Divide $x$ by $1$ .

$x = \frac{- 1}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{4}$

Set $3 x + 4$ equal to $0$ and solve for $x$ .

Set $3 x + 4$ equal to $0$ .

$3 x + 4 = 0$

Solve $3 x + 4 = 0$ for $x$ .

Subtract $4$ from both sides of the equation.

$3 x = - 4$

Divide each term in $3 x = - 4$ by $3$ and simplify.

Divide each term in $3 x = - 4$ by $3$ .

$\frac{3 x}{3} = \frac{- 4}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 4}{3}$

Divide $x$ by $1$ .

$x = \frac{- 4}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{4}{3}$

The final solution is all the values that make $(9 x + 7) (4 x + 1) (3 x + 4) = 0$ true.

$x = - \frac{7}{9}, - \frac{1}{4}, - \frac{4}{3}$

Find the Roots (Zeros) (9x+7)(4x+1)(3x+4)=0

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