Find the Roots (Zeros) f(x)=16-x

$f (x) = 16 - x$

Step 1

Set $16 - x$ equal to $0$ .

$16 - x = 0$

Step 2

Solve for $x$ .

Subtract $16$ from both sides of the equation.

$- x = - 16$

Divide each term in $- x = - 16$ by $- 1$ and simplify.

Divide each term in $- x = - 16$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 16}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 16}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 16}{- 1}$

Simplify the right side.

Divide $- 16$ by $- 1$ .

$x = 16$

Step 3