Find the Roots (Zeros) f(x)=-2((1^x)/3)

$f (x) = - 2 (\frac{1^{x}}{3})$

Set $- 2 \frac{1^{x}}{3}$ equal to $0$ .

$- 2 \frac{1^{x}}{3} = 0$

Solve for $x$ .

Simplify $- 2 \frac{1^{x}}{3}$ .

One to any power is one.

$- 2 (\frac{1}{3}) = 0$

Combine $- 2$ and $\frac{1}{3}$ .

$\frac{- 2}{3} = 0$

Move the negative in front of the fraction.

$- \frac{2}{3} = 0$

$- \frac{2}{3} = 0$

Set the numerator equal to zero.

$2 = 0$

Since $2 \neq 0$ , there are no solutions.

No solution

No solution

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