Find the Roots (Zeros) f(x)=2-4sin(x)

$f (x) = 2 - 4 \sin (x)$

Step 1

Set $2 - 4 \sin (x)$ equal to $0$ .

$2 - 4 \sin (x) = 0$

Step 2

Solve for $x$ .

Subtract $2$ from both sides of the equation.

$- 4 \sin (x) = - 2$

Divide each term in $- 4 \sin (x) = - 2$ by $- 4$ and simplify.

Divide each term in $- 4 \sin (x) = - 2$ by $- 4$ .

$\frac{- 4 \sin (x)}{- 4} = \frac{- 2}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 \sin (x)}{- 4} = \frac{- 2}{- 4}$

Divide $\sin (x)$ by $1$ .

$\sin (x) = \frac{- 2}{- 4}$

Simplify the right side.

Cancel the common factor of $- 2$ and $- 4$ .

Factor $- 2$ out of $- 2$ .

$\sin (x) = \frac{- 2 (1)}{- 4}$

Cancel the common factors.

Factor $- 2$ out of $- 4$ .

$\sin (x) = \frac{- 2 \cdot 1}{- 2 \cdot 2}$

Cancel the common factor.

$\sin (x) = \frac{- 2 \cdot 1}{- 2 \cdot 2}$

Rewrite the expression.

$\sin (x) = \frac{1}{2}$

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$x = \arcsin (\frac{1}{2})$

Simplify the right side.

The exact value of $\arcsin (\frac{1}{2})$ is $\frac{π}{6}$ .

$x = \frac{π}{6}$

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $π$ to find the solution in the second quadrant.

$x = π - \frac{π}{6}$

Simplify $π - \frac{π}{6}$ .

To write $π$ as a fraction with a common denominator, multiply by $\frac{6}{6}$ .

$x = π \cdot \frac{6}{6} - \frac{π}{6}$

Combine fractions.

Combine $π$ and $\frac{6}{6}$ .

$x = \frac{π \cdot 6}{6} - \frac{π}{6}$

Combine the numerators over the common denominator.

$x = \frac{π \cdot 6 - π}{6}$

Simplify the numerator.

Move $6$ to the left of $π$ .

$x = \frac{6 \cdot π - π}{6}$

Subtract $π$ from $6 π$ .

$x = \frac{5 π}{6}$

Find the period of $\sin (x)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

The period of the $\sin (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{π}{6} + 2 π n, \frac{5 π}{6} + 2 π n$ , for any integer $n$

Step 3

Find the Roots (Zeros) f(x)=2-4sin(x)

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