Find the Roots (Zeros) f(x)=2(x+3)^2

$f (x) = 2 {(x + 3)}^{2}$

Step 1

Set $2 {(x + 3)}^{2}$ equal to $0$ .

$2 {(x + 3)}^{2} = 0$

Step 2

Solve for $x$ .

Divide each term in $2 {(x + 3)}^{2} = 0$ by $2$ and simplify.

Divide each term in $2 {(x + 3)}^{2} = 0$ by $2$ .

$\frac{2 {(x + 3)}^{2}}{2} = \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 {(x + 3)}^{2}}{2} = \frac{0}{2}$

Divide ${(x + 3)}^{2}$ by $1$ .

${(x + 3)}^{2} = \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

${(x + 3)}^{2} = 0$

Set the $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

Step 3