Find the Roots (Zeros) f(x)=-3/8x^4-x^3+2x^2+5

$f (x) = - \frac{3}{8} x^{4} - x^{3} + 2 x^{2} + 5$

Step 1

Set $- \frac{3}{8} x^{4} - x^{3} + 2 x^{2} + 5$ equal to $0$ .

$- \frac{3}{8} x^{4} - x^{3} + 2 x^{2} + 5 = 0$

Step 2

Solve for $x$ .

Simplify each term.

Combine $x^{4}$ and $\frac{3}{8}$ .

$- \frac{x^{4} \cdot 3}{8} - x^{3} + 2 x^{2} + 5 = 0$

Move $3$ to the left of $x^{4}$ .

$- \frac{3 x^{4}}{8} - x^{3} + 2 x^{2} + 5 = 0$

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx - 4.14194612, 1.93403591$

Step 3