Find the Roots (Zeros) f(x)=-(x+1)(x-3)(x+2)

$f (x) = - (x + 1) (x - 3) (x + 2)$

Set $- (x + 1) (x - 3) (x + 2)$ equal to $0$ .

$- (x + 1) (x - 3) (x + 2) = 0$

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x - 3 = 0$

$x + 2 = 0$

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

The final solution is all the values that make $- (x + 1) (x - 3) (x + 2) = 0$ true.

$x = - 1, 3, - 2$