Find the Roots (Zeros) f(x)=(x^2+x-6)/(x^2+x-20)

$f (x) = \frac{x^{2} + x - 6}{x^{2} + x - 20}$

Step 1

Set $\frac{x^{2} + x - 6}{x^{2} + x - 20}$ equal to $0$ .

$\frac{x^{2} + x - 6}{x^{2} + x - 20} = 0$

Step 2

Solve for $x$ .

Set the numerator equal to zero.

$x^{2} + x - 6 = 0$

Solve the equation for $x$ .

Factor $x^{2} + x - 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 6$ and whose sum is $1$ .

$- 2, 3$

Write the factored form using these integers.

$(x - 2) (x + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 2 = 0$

$x + 3 = 0$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $(x - 2) (x + 3) = 0$ true.

$x = 2, - 3$

Step 3

Find the Roots (Zeros) f(x)=(x^2+x-6)/(x^2+x-20)

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