Find the Roots (Zeros) f(x)=x^3+14x-8x^2-1

$f (x) = x^{3} + 14 x - 8 x^{2} - 1$

Set $x^{3} + 14 x - 8 x^{2} - 1$ equal to $0$ .

$x^{3} + 14 x - 8 x^{2} - 1 = 0$

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx 0.07457708, 2.44807056, 5.47735234$