Find the Roots (Zeros) f(x)=x^3+2x^2-3x-3

$f (x) = x^{3} + 2 x^{2} - 3 x - 3$

Step 1

Set $x^{3} + 2 x^{2} - 3 x - 3$ equal to $0$ .

$x^{3} + 2 x^{2} - 3 x - 3 = 0$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx - 2.69962814, - 0.76087672, 1.46050487$

Step 3