Find the Roots (Zeros) f(x)=(x+3)/(2x^2-6)

$f (x) = \frac{x + 3}{2 x^{2} - 6}$

Step 1

Set $\frac{x + 3}{2 x^{2} - 6}$ equal to $0$ .

$\frac{x + 3}{2 x^{2} - 6} = 0$

Step 2

Solve for $x$ .

Set the numerator equal to zero.

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

Step 3