Find the Roots (Zeros) f(x)=(x-7)^2-64

$f (x) = {(x - 7)}^{2} - 64$

Step 1

Set ${(x - 7)}^{2} - 64$ equal to $0$ .

${(x - 7)}^{2} - 64 = 0$

Step 2

Solve for $x$ .

Add $64$ to both sides of the equation.

${(x - 7)}^{2} = 64$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 7 = \pm \sqrt{64}$

Simplify $\pm \sqrt{64}$ .

Rewrite $64$ as $8^{2}$ .

$x - 7 = \pm \sqrt{8^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x - 7 = \pm 8$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x - 7 = 8$

Move all terms not containing $x$ to the right side of the equation.

Add $7$ to both sides of the equation.

$x = 8 + 7$

Add $8$ and $7$ .

$x = 15$

Next, use the negative value of the $\pm$ to find the second solution.

$x - 7 = - 8$

Move all terms not containing $x$ to the right side of the equation.

Add $7$ to both sides of the equation.

$x = - 8 + 7$

Add $- 8$ and $7$ .

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 15, - 1$

Step 3