Find the Roots (Zeros) f(x)=x(x-3)^2

$f (x) = x {(x - 3)}^{2}$

Step 1

Set $x {(x - 3)}^{2}$ equal to $0$ .

$x {(x - 3)}^{2} = 0$

Step 2

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

${(x - 3)}^{2} = 0$

Set $x$ equal to $0$ .

$x = 0$

Set ${(x - 3)}^{2}$ equal to $0$ and solve for $x$ .

Set ${(x - 3)}^{2}$ equal to $0$ .

${(x - 3)}^{2} = 0$

Solve ${(x - 3)}^{2} = 0$ for $x$ .

Set the $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

The final solution is all the values that make $x {(x - 3)}^{2} = 0$ true.

$x = 0, 3$

Step 3