Find the Roots (Zeros) p(x)=-2(x-3)(x-11)

$p (x) = - 2 (x - 3) (x - 11)$

Step 1

Set $- 2 (x - 3) (x - 11)$ equal to $0$ .

$- 2 (x - 3) (x - 11) = 0$

Step 2

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 3 = 0$

$x - 11 = 0$

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Set $x - 11$ equal to $0$ and solve for $x$ .

Set $x - 11$ equal to $0$ .

$x - 11 = 0$

Add $11$ to both sides of the equation.

$x = 11$

The final solution is all the values that make $- 2 (x - 3) (x - 11) = 0$ true.

$x = 3, 11$

Step 3