Find the Roots (Zeros) q(x)=(x+8)/(x^2-10x+9)

$q (x) = \frac{x + 8}{x^{2} - 10 x + 9}$

Step 1

Set $\frac{x + 8}{x^{2} - 10 x + 9}$ equal to $0$ .

$\frac{x + 8}{x^{2} - 10 x + 9} = 0$

Step 2

Solve for $x$ .

Set the numerator equal to zero.

$x + 8 = 0$

Subtract $8$ from both sides of the equation.

$x = - 8$

Step 3