Find the Roots/Zeros Using the Rational Roots Test x^3+5x^2-7x-35

$x^{3} + 5 x^{2} - 7 x - 35$

Step 1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 5, \pm 7, \pm 35$

$q = \pm 1$

Step 2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm 5, \pm 7, \pm 35$

Step 3

Substitute the possible roots one by one into the polynomial to find the actual roots. Simplify to check if the value is $0$ , which means it is a root.

${(- 5)}^{3} + 5 {(- 5)}^{2} - 7 \cdot - 5 - 35$

Step 4

Simplify the expression. In this case, the expression is equal to $0$ so $x = - 5$ is a root of the polynomial.

Simplify each term.

Raise $- 5$ to the power of $3$ .

$- 125 + 5 {(- 5)}^{2} - 7 \cdot - 5 - 35$

Raise $- 5$ to the power of $2$ .

$- 125 + 5 \cdot 25 - 7 \cdot - 5 - 35$

Multiply $5$ by $25$ .

$- 125 + 125 - 7 \cdot - 5 - 35$

Multiply $- 7$ by $- 5$ .

$- 125 + 125 + 35 - 35$

Simplify by adding and subtracting.

Add $- 125$ and $125$ .

$0 + 35 - 35$

Add $0$ and $35$ .

$35 - 35$

Subtract $35$ from $35$ .

$0$

Step 5

Since $- 5$ is a known root, divide the polynomial by $x + 5$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{x^{3} + 5 x^{2} - 7 x - 35}{x + 5}$

Step 6

Next, find the roots of the remaining polynomial. The order of the polynomial has been reduced by $1$ .

Place the numbers representing the divisor and the dividend into a division-like configuration.

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0			\xa0

The first number in the dividend $(1)$ is put into the first position of the result area (below the horizontal line).

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0			\xa0
	$1$

Multiply the newest entry in the result $(1)$ by the divisor $(- 5)$ and place the result of $(- 5)$ under the next term in the dividend $(5)$ .

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0	$- 5$		\xa0
	$1$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0	$- 5$		\xa0
	$1$	$0$

Multiply the newest entry in the result $(0)$ by the divisor $(- 5)$ and place the result of $(0)$ under the next term in the dividend $(- 7)$ .

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0	$- 5$	$0$	\xa0
	$1$	$0$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0	$- 5$	$0$	\xa0
	$1$	$0$	$- 7$

Multiply the newest entry in the result $(- 7)$ by the divisor $(- 5)$ and place the result of $(35)$ under the next term in the dividend $(- 35)$ .

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0	$- 5$	$0$	$35$
	$1$	$0$	$- 7$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 5$	$1$	$5$	$- 7$	$- 35$
	\xa0	$- 5$	$0$	$35$
	$1$	$0$	$- 7$	$0$

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$1 x^{2} + 0 x - 7$

Simplify the quotient polynomial.

$x^{2} - 7$

Step 7

Solve the equation to find any remaining roots.

Add $7$ to both sides of the equation.

$x^{2} = 7$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{7}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \sqrt{7}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \sqrt{7}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{7}, - \sqrt{7}$

Step 8

The polynomial can be written as a set of linear factors.

$(x + 5) (x - \sqrt{7}) (x + \sqrt{7})$

Step 9

These are the roots (zeros) of the polynomial $x^{3} + 5 x^{2} - 7 x - 35$ .

$x = - 5, \sqrt{7}, - \sqrt{7}$

Step 10

The result can be shown in multiple forms.

Exact Form:

$x = - 5, \sqrt{7}, - \sqrt{7}$

Decimal Form:

$x = - 5, 2.64575131 \dots, - 2.64575131 \dots$

Step 11

Find the Roots/Zeros Using the Rational Roots Test x^3+5x^2-7x-35

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