Find the Roots (Zeros) x^2+121=22x

$x^{2} + 121 = 22 x$

Step 1

Subtract $22 x$ from both sides of the equation.

$x^{2} + 121 - 22 x = 0$

Step 2

Factor using the perfect square rule.

Rearrange terms.

$x^{2} - 22 x + 121 = 0$

Rewrite $121$ as $11^{2}$ .

$x^{2} - 22 x + 11^{2} = 0$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$22 x = 2 \cdot x \cdot 11$

Rewrite the polynomial.

$x^{2} - 2 \cdot x \cdot 11 + 11^{2} = 0$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 11$ .

${(x - 11)}^{2} = 0$

Step 3

Set the $x - 11$ equal to $0$ .

$x - 11 = 0$

Step 4

Add $11$ to both sides of the equation.

$x = 11$

Step 5