Find the Roots (Zeros) x^2+24=14x

$x^{2} + 24 = 14 x$

Step 1

Subtract $14 x$ from both sides of the equation.

$x^{2} + 24 - 14 x = 0$

Step 2

Factor $x^{2} + 24 - 14 x$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $24$ and whose sum is $- 14$ .

$- 12, - 2$

Write the factored form using these integers.

$(x - 12) (x - 2) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 12 = 0$

$x - 2 = 0$

Step 4

Set $x - 12$ equal to $0$ and solve for $x$ .

Set $x - 12$ equal to $0$ .

$x - 12 = 0$

Add $12$ to both sides of the equation.

$x = 12$

Step 5

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Step 6

The final solution is all the values that make $(x - 12) (x - 2) = 0$ true.

$x = 12, 2$

Step 7

Find the Roots (Zeros) x^2+24=14x

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